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Posted

You have a fair coin, and when tossing it you are looking for patterns, either HTH or HTT, you count the number of tosses it takes until you see each pattern.

 

You do this many times and get an average number of tosses for each pattern. Which of the following is true?

 

a) The average number of tosses until HTH is larger than the average number of tosses for HTT

b) The average number of tosses until HTH is the same as the average number of tosses for HTT

c) The average number of tosses until HTH is smaller than the average number of tosses for HTT

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Posted
You have a fair coin, and when tossing it you are looking for patterns, either HTH or HTT, you count the number of tosses it takes until you see each pattern.

 

You do this many times and get an average number of tosses for each pattern. Which of the following is true?

 

a) The average number of tosses until HTH is larger than the average number of tosses for HTT

b) The average number of tosses until HTH is the same as the average number of tosses for HTT

c) The average number of tosses until HTH is smaller than the average number of tosses for HTT

 

your not doing a maths degree are you???

 

takes me right back!!

Posted

I'd say B,

 

It's a fair coin the result is either H or T totally at random (given a random fair toss [Not sure i really give a toss])

 

So there is no way that A or C can apply. If they do then you have not conducted enough coin tosses to get a true average reading.

 

It's like tossing it three times and getting HTH then saying "on average this coin always comes up Heads" statistically true but massively flawed.

Posted (edited)

The answer is B.

 

You're going to get a result the first time you get a HT turn up in the sequence, the next toss determining the result.

The average number of tosses before HT comes up will be the same for either result.

And since the coin is fair then the H or T on the third coin in the sequence will be 50/50.

 

If the target patterns differed by more than just the final toss then you could get a difference. i.e. The target patterns were HTH & TTH.

Edited by high.as.a.kite
Posted
Got any stats on buttered toast...

 

the mythbusters did an experiment on it. here are the notes from the show

 

Buttered Toast: which side does it fall on?

 

There were two things being tested here: 1. If buttered toast falls off the table, does it prefer to land butter side down 2. If a buttered toast falls through the air, which side does it prefer to fall on?

 

First (Adam's) rig: Adam's rig most closely replicated a piece of toast falling off of a table top. Testing with a control sample of unbuttered test, the dominant behavior was for the toast to flip once and land top side down. They didn't need to do any more testing with actual buttered toast, as the rig clearly had a bias.

 

Second (Jamie's) rig: Jamie's rig tested whether or not, all things being equal, which side toast prefers to fall on. It shoots toast straight down.

 

With control sample testing, toast kept landing down. Once again they were statistically challenged, as they stopped after 10 samples. They determined that 3 ups and 7 downs was enough to show a clear down bias, and once again, if just one of those had been different, they it would have been 4 ups and 6 downs, which doesn't seem biased at all.

 

Third rig: based on Jamie's original design, but with way more over-engineering to be more automated, regular, and MythBuster-y. A conveyor belt toaster dropped the toast off onto a second conveyor belt that carried toast over to Adam, who marked the toast and loaded it into a dropper that was then released with a switch.

 

* 11 up and 13 down with control sample

* 12 up and 12 down with buttered sample

 

They determined this to be "less biased", so they then brought it to the roof of MythBusters HQ. From the top of the roof:

 

* 26 up and 22 down with control sample

* 29 up and 19 down with buttered sample

 

Jamie's theory was that for a lot of the buttered toast that landed butter side up, the buttered side was pressed in, forming a cup that affected the way the toast dropped.

Posted
The answer is B.

 

You're going to get a result the first time you get a HT turn up in the sequence, the next toss determining the result.

The average number of tosses before HT comes up will be the same for either result.

And since the coin is fair then the H or T on the third coin in the sequence will be 50/50.

 

I agree entirely...

 

Ok anything, explain how a 'fair' coin can be more likely to generate one sequence than another (the sequences being the same length)?

Posted

its simple realy

because the coin is "fair" avrage for htt will eb the same to hth out of 100 tosses..

that would only work computer simulated though..

 

you can actuly controll the outcome of a coin toss by how u flick it :o

 

so the answer could be a, b and c..

Posted

Yeah, this is a trick question with something non-intuitive going on I reckon....

 

Basically, you keep tossing coins until you get a HT, then the next toss is what decides it...which is 50/50. You'll probably get a bunch of TTH and THT in the process...

 

But....if the first coin is a H, you're then looking at cutting out the first of the HT...

 

Intuitively I'd say it's 50/50, but given the odds of Anything being a cleverdick (tending to one ;)) I'm going with HTH being more likely, (a).

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